Posted by **Abi** on Thursday, June 20, 2013 at 8:25pm.

I'm supposed to graph y= 4+2sin (pi/6 t -pi/5)

i have the vertical shift d=4

amplitude 2

level line y=4

crest line y=6

trough line y=2

but i am not sure what the period is

formula for period 2pi/b

in this case 2pi/pi/6 => 12pi/pi

do the pi's cancel, leaving the period at 12????

am i doing this right?

- Pre-cal -
**Reiny**, Thursday, June 20, 2013 at 10:28pm
You are correct,

for y = sin kx, the period is 2π/k

in your case you have 2π/(π/6)

= 2π(6/π) = 12 (units of t)

I am surprised you don't have to find the phase shift

to get the correct phase shift your equation should be in the form

y = 4 + 2sin[ (π/6)( t - 6/5) ]

so the phase shift is 6/5 units to the right.

- Pre-cal -
**Abi**, Friday, June 21, 2013 at 11:09pm
I did have to find those too but i was stuck on the Period!

thank you so very much!

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