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March 29, 2015

March 29, 2015

Posted by **Anonymous** on Thursday, June 20, 2013 at 5:36pm.

- Statistics -
**PsyDAG**, Friday, June 21, 2013 at 12:55pmAssuming a normal distribution:

Z = (score-mean)/SEm

SEm = SD/√n = 500/√100 = 500/10 = 50

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score.

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