Posted by **Kim** on Thursday, June 20, 2013 at 1:02pm.

A total of $12,000 is invested in two funds paying 9% and 11% simple interest. If the yearly interest is $1,180, how much of the $12,000 is invested at each rate?

There seems to be a decimal in this problem if so how do I get rid of it verifying x,y?

- Math Algebra1A -
**Steve**, Thursday, June 20, 2013 at 2:21pm
If x is invested at 9%, 12000-x is invested at 11%. So, adding up the interest,

.09x + .11(12000-x) = 1180

x = 7000

## Answer this Question

## Related Questions

- algebra - A total of $12,000 is invested in two funds paying 9% and 11% simple ...
- Math - A total of 10,000 is invested into two funds paying 7.5% and 9% simple ...
- Algebra - I invested $42,000 in three funds paying 5%, 7%, and 9% simple ...
- algebra - A total of $80,000 is invested in two funds paying 2.3% and 3.1% ...
- algebra - suppose you invest $15,000 in two funds paying 11 1/2% and 14% simple ...
- college algebra - suppose you invest $15,000 in two funds paying 11 1/2%and 14% ...
- algebra - Dilbert invests a total of $14,000 in two accounts paying 9% and 15% ...
- Math - You invested $14,000 in two accounts paying 5% and 9% annual interest, ...
- algebra - Larry Mitchel invested part of his $32,000 advance at 7% annual simple...
- math - you invested $4000 in two accounts paying 2% and 9% annual interest, ...

More Related Questions