Posted by **mysterychicken** on Thursday, June 20, 2013 at 11:26am.

Not sure about this question...

1. State the range for the function f(x) = -log 1/2(base) (x-1) + 2

..help?

- math -
**mysterychicken**, Thursday, June 20, 2013 at 11:29am
I think its (-infinity, infinity)

- math -
**Steve**, Thursday, June 20, 2013 at 11:37am
You know that the range for log(x) is all real numbers.

Similarly, the range for log_2(x) is all real numbers, since log_2(x) = lnx/ln2

log_(1/2)(x) = -log_2(x) since 1/2 = 2^(-1)

So, log_(1/2)x = -lnx/ln2

log_(1/2)(x-1) is just the same graph, shifted right by 1

log_(1/2)(x-1)+2 is the same graph, shifted up by 2

The range is still all reals.

Visit wolfamalpha.com and type in

log_2(x-1)+2

- math -
**mysterychicken**, Thursday, June 20, 2013 at 11:41am
Got it!

- math -
**Jorge**, Thursday, June 20, 2013 at 11:44am
The range is basically all the values that can come out from plugging something in (in other words, every answer that the equation can have). In order to find the range, you need to graph this equation. Once you have the graph, find which point the asymptote(the dashed line) lies. This is the first value that goes into the range. Next, you find which side the actual line goes to. If it goes to the right, then the range is (y coordinate of asymptote, ∞). If it goes to the left, then it is (-∞, y coordinate of asymptote) hope it helps :)

ps. i like your username xD

- math -
**Jorge**, Thursday, June 20, 2013 at 11:45am
well nevermind ._.

- math -
**mysterychicken**, Thursday, June 20, 2013 at 11:46am
Thanks for the compliment haha

Been using this username on Jiskha for 5 years now

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