Take two glasses put 20g sugar in 2l water in first glass and put 15g sugar in 15ml water in second glass now Chekh out which one will be more concentrated and find out molarity normolity of both
To determine which solution is more concentrated and calculate the molarity and normality of both solutions, we need to understand the concepts involved.
Concentration: Concentration measures the amount of solute dissolved in a given amount of solvent or solution. It can be expressed in different units such as grams per liter (g/L), grams per milliliter (g/mL), molarity (M), or normality (N).
Molarity (M): Molarity is a measure of concentration commonly used in chemistry. It represents the number of moles of solute dissolved in one liter of solution. Molarity (M) is calculated using the formula:
Molarity (M) = (moles of solute) / (volume of solution in liters)
Normality (N): Normality is another measure of concentration, especially used for acid-base reactions. It represents the number of gram equivalents of solute per liter of solution. Normality (N) is calculated using the formula:
Normality (N) = (gram equivalents of solute) / (volume of solution in liters)
Now, let's calculate the concentration, molarity, and normality for both solutions:
For the first solution (20g sugar in 2L water):
- Concentration: 20g sugar in 2L water (g/L)
- Molarity: To calculate molarity, we need to know the molar mass of sugar. Assuming sugar to be sucrose (C12H22O11) with a molar mass of 342.3 g/mol, we can convert grams of sugar to moles using the formula:
Moles of sugar = (grams of sugar) / (molar mass of sugar)
Molarity (M) = Moles of sugar / Volume of solution in liters
For the second solution (15g sugar in 15ml water):
- Concentration: 15g sugar in 15mL water (g/mL)
- Molarity: Since the volume is given in milliliters, we need to convert it to liters (15 mL = 0.015 L). Again, we can use the molar mass of sugar to convert grams of sugar to moles. Then calculate molarity using the same formula as above.
- Normality: Normality is used mainly for acid-base reactions, and since sugar is not an acid or base, we cannot calculate its normality.
So, by calculating the molarity of both solutions, we can determine which one is more concentrated.