Wednesday

April 23, 2014

April 23, 2014

Posted by **Shadow** on Tuesday, June 18, 2013 at 11:15pm.

I use the change of base formula and got log6/log2 * log8/log6

Which become

log6/log2 * log2()^3/ log 6

I'm stuck here thanks.

- Math -
**Steve**, Wednesday, June 19, 2013 at 11:26amyou are correct in that you wind up with

log6/log2 * log8/log6

Now, you almost had it, since you recognized (I think) that 8 = 2^3. So, you have

= log8/log2

= 3log2/log2

= 3

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