Posted by **Shadow** on Tuesday, June 18, 2013 at 11:15pm.

The problem I have to solve is log with base 2 ^6 multiply by log base 6 ^ 8.

I use the change of base formula and got log6/log2 * log8/log6

Which become

log6/log2 * log2()^3/ log 6

I'm stuck here thanks.

- Math -
**Steve**, Wednesday, June 19, 2013 at 11:26am
you are correct in that you wind up with

log6/log2 * log8/log6

Now, you almost had it, since you recognized (I think) that 8 = 2^3. So, you have

= log8/log2

= 3log2/log2

= 3

## Answer this Question

## Related Questions

- Logarithms - I'm working on logarithmic equations and I'm stuck on how my book ...
- Algebra 2 - -Explain the difference between log base b (mn) and ( log base b of ...
- Logarithmic Algebra - let log2=a, log3=b, and log5=c. express the indicated ...
- Advanced Functions/ Precalculus Log - 1. Evaluate 4^(log base4 64) + 10^(log100...
- Math - log(x-2) +log8 (x-4) =log6 (x-1)
- precalulus - Ok feeling kinda dumb because this isn't coming out right. I know ...
- math - Use the Laws of logarithms to rewrite the expression log(base 2)(11x(x-9...
- Trigonometry - Every point (x,y) on the curve y=log(3x)/log2 is transferred to a...
- Trig - log base b 64 - log base b 16 = log base 4 16 solve for the variable.. i...
- Calculus - Find the inverse of each relation: y = (0.5)^(x+2) and y = 3log base ...

More Related Questions