Wednesday

July 23, 2014

July 23, 2014

Posted by **Cole** on Tuesday, June 18, 2013 at 10:24pm.

A) 1+5 + (5^2)/(2!)+(5^3)/(3!)+(5^4)/(4!)+...+ (5^k)/(k!)+...=

B) 1-(2^2)/(2!)+(2^4)/(4!)-(2^6)/(6!)+...+((-1)^(k)2^(2k))/((2k)!) +...=

- Calculus -
**Steve**, Wednesday, June 19, 2013 at 11:36ame^x = 1+x+x^2/2! + ...

Looks like the series is e^5

Since cos(x) = 1 - x^2/2! + ...

Looks like the series is cos(2)

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