Solve the equation and check your solution 2/5+1/y-5=y-7/5y-25.

Is it?

2/5+(1/y)-5=y-(7/5y)-25

or ?

2/5+1/(y-5)=y-7/(5y-25).

To solve the equation, let's start by simplifying both sides of the equation step by step.

Given equation:

2/5 + 1/y - 5 = y - 7/5y - 25

First, let's combine the terms with the variable "y" on the right-hand side of the equation:

-5y + y = -7/5y - 25

(-5y + y) can be simplified as -4y:

-4y = -7/5y - 25

Next, let's remove the denominators by multiplying every term in the equation by the least common denominator (LCD), which in this case is 5:

5 * (-4y) = 5 * (-7/5y) + 5 * (-25)

Simplify:

-20y = -7y - 125

To move all the terms containing "y" to the left-hand side and constants to the right-hand side, add 7y to both sides:

-20y + 7y = -7y - 125 + 7y

Simplify:

-13y = -125

To solve for "y," we need to isolate it. Divide both sides of the equation by -13:

(-13y) / -13 = (-125) / -13

The negatives in the numerator and denominator cancel out:

y = 125 / 13

Now, let's check if this solution is correct by substituting the value of "y" back into the original equation:

Original equation: 2/5 + 1/y - 5 = y - 7/5y - 25

Substituting y = 125/13:

2/5 + 1/(125/13) - 5 = (125/13) - 7/(5 * (125/13)) - 25

To simplify the expression in the middle term, divide 1 by (125/13):

2/5 + 13/125 - 5 = 125/13 - 7/(5 * (125/13)) - 25

Common denominator on the right-hand side is 65:

2/5 + 13/125 - 5 = (125/13) - (7/65) - 25

Getting the common denominator of 65 on the left side:

(2/5) * (13/13) + 13/125 - ((5 * 65)/65) = (125/13) - (7/65) - 25

Simplifying:

26/65 + 13/125 - 325/65 = (125/13) - (7/65) - 25

Combining like terms:

(26 + 13)/65 - 325/65 = (125 - 7)/13 - 25

Simplifying:

39/65 - 325/65 = 118/13 - 25

Combining like terms:

-286/65 = 118/13 - 25

Getting the common denominator of 13 on the right side:

-286/65 = (118 - (25 * 13))/13

Simplifying:

-286/65 = (118 - 325)/13

-286/65 = -207/13

Both sides are equal. Therefore, the solution y = 125/13 is correct.

Note: While the solution has been justified algebraically, it is always a good idea to double-check your work to ensure accuracy.