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November 27, 2014

November 27, 2014

Posted by **Anonymous** on Tuesday, June 18, 2013 at 4:28pm.

f(t) = 7 t + 3/t

relative maximum (x, y) =

relative minimum (x, y) =

- Calculus -
**Steve**, Tuesday, June 18, 2013 at 4:32pmf' = 7-3/t^2

f'=0 when t=±√(3/7)

f" = 6/t^3

f" > 0 when t>0 so min at t=√(3/7)

f" < 0 when t<0 so max at t=-√(3/7)

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