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Find the relative extrema, if any, of the function. Use the second derivative test, if applicable. (If an answer does not exist, enter DNE.)
f(t) = 7 t + 3/t
relative maximum (x, y) =
relative minimum (x, y) =

  • Calculus - ,

    f' = 7-3/t^2
    f'=0 when t=±√(3/7)

    f" = 6/t^3
    f" > 0 when t>0 so min at t=√(3/7)
    f" < 0 when t<0 so max at t=-√(3/7)

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