posted by Nogard on .
A football is punted at an angle of 44.6 with the horizontal. if it stays in the air for 3.6 seconds, what was the initial velocity of the football?
The vertical component of the velocity is
Vy = V cos 44.6 = .712V
The height of the ball in feet is given by
h(t) = (.712V)t - 16t^2
So, if h(t) = 0 when t=3.6,
.712V*3.6 - 16*3.6^2 = 0
V = 80.9 ft/s
Guy's a pretty decent kicker, since the average kickoff speed is about 50 mph = 73 ft/s