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March 29, 2015

March 29, 2015

Posted by **Morgan** on Tuesday, June 18, 2013 at 3:25pm.

- Calc -
**Steve**, Tuesday, June 18, 2013 at 3:56pmIf the woman is x feet from the pole, and her shadow is of length s, then

s/6 = (x+s)/16

s/6 = x/16 + s/16

5/48 s = x/16

s = 3/5 x

So, unlike the problem where some angle is steadily changing, here the shadow is always 3/5 as long as the distance from the pole.

Since dx/dt = 6, ds/dt = 18/5

No matter how far she is from the pole.

However, that is not the answer to the question. The tip of her shadow is moving 18/5 from the woman. Add to that her own walking speed, and we see that the tip of the shadow is moving at 18/5 + 6 = 48/5 ft/s

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