Posted by GK on Tuesday, June 18, 2013 at 12:58pm.
how do i calculate the point on the curve when the ordinate changes 8 times faster than abscissa in the equation 6y=x^3+2

BEST  Steve, Tuesday, June 18, 2013 at 3:05pm
the conditions mean that the slope is 8.
y' is the slope, and since
6y' = 3x^2
y' = 1/2 x^2
If 1/2 x^2 = 8, then x = 4
So, at (4,11) the slope is 8

BEST  GK, Wednesday, June 19, 2013 at 12:48am
thank you
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