Posted by
**Tom 12** on
.

Consider the following table and use the formulas that are given for computing the correlation coefficient. (Give your answer correct to two decimal places.)

x 1 1 0 0 0

y 7 3 5 6 6

r =

n

xy

−

x

y

n

x2

−

x

2

n

y2

−

y

2

(1)

r =

SS(xy)

SS(x) ยท SS(y)

(2)

This is what I done (2)(27)/5 =10.8 for ss(xy) then 2^/5=.8 for SS(x), ten (27^)/5=145.8 for SS(y), then I put 10.8 over sqrt.8 X 145.8 = 1.00