Posted by **jack** on Tuesday, June 18, 2013 at 12:24pm.

A 999-digit number starts with 9. Every 2 consecutive digits is divisible by 17 or 23. There are 2 possibilities for the last 3 digits. What is the sum of these 2 possibilities?

## Answer This Question

## Related Questions

- Maths - I’m a 4-digit number. My 1st 2 digits from the left are divisible by 5. ...
- math - I am thinking of a two-digit number in which the sum of the digits is 9 ...
- math - i am a 3-digit number divisible by 3. my tens digit is 3 times as great ...
- math - i am a 3 digit number divisible by 3.my tens digit is 3 times as great as...
- Math - I am a 3 digit number divisible by 3. My tens digit is 3 times as great ...
- Math - I am a 3digit number divisible by 3. my tens digit is three times as ...
- MATH - Need Answer to the Following Please: Using the 9 digits, 1, 2, 3, 4, 5, 6...
- Math - Using the 9 digits, 1, 2, 3, 4, 5, 6,7, 8 and 9 you can arrange four ...
- 6th grade - i am a 3 digit number divisible by 3. my tens digit is 3 times as ...
- Math Help Please - Can you Please explain the answer that I received of 2469? It...

More Related Questions