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**jack** on
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A 999-digit number starts with 9. Every 2 consecutive digits is divisible by 17 or 23. There are 2 possibilities for the last 3 digits. What is the sum of these 2 possibilities?

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March 25, 2017
Posted by
**jack** on
.

A 999-digit number starts with 9. Every 2 consecutive digits is divisible by 17 or 23. There are 2 possibilities for the last 3 digits. What is the sum of these 2 possibilities?

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