Post a New Question


posted by .

Find the equation of the tangent line to the curve y=2tan(x) at the point (pi/4,2).

  • Calculus -

    y'(x) = 2sec^2(x)
    y'(pi/4) = 2(2) = 4

    So, now you have a point and a slope, so the line is ?

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question