Posted by **Shane** on Tuesday, June 18, 2013 at 1:58am.

Find two geometric progressions having: 54 as third term and 27/32 as ninth term.

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**Steve**, Tuesday, June 18, 2013 at 4:17am
T9 is the 6th term after T3, so

27/32 = 54*r^6

1/64 = r^6

r = ± 1/2

I think you can do the rest.

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**Shane**, Tuesday, August 6, 2013 at 4:38pm
Expand (1-x)^4.Hence find S if S = (1-x^3)^4 - (1-x^3)^3 + 6(1-x^3)^2 - 4(1-x^3) + 1.

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