Carlos Molly and Simon had to share $100.

Molly had 3 times as much money as Simon.
Carlos had 2 times as much money as Molly.

How much money did Carlos get?
How much money did Simon get?

S = Simon

S + 3S + 2(3S) = 100

10S = 10

10

Simon received $10

Carlos received $60

60 and 10

To solve this problem, we can break it down step by step.

Step 1: Molly had 3 times as much money as Simon.
Let's assume Simon had x amount of money.
Therefore, Molly had 3x amount of money.

Step 2: Carlos had 2 times as much money as Molly.
Since Molly had 3x amount of money, Carlos had 2 * (3x) = 6x amount of money.

Step 3: The three of them had to share $100.
The total amount of money they all had sums up to x + 3x + 6x = 10x.

Step 4: We know that the total amount of money they shared is $100.
So, 10x = $100.

Step 5: We can now solve for x.
Dividing both sides of the equation by 10, we get:
x = $100 / 10 = $10.

Step 6: Now, we can find the amount of money each person received.
Simon had x amount of money, which is $10.
Molly had 3x amount of money, which is 3 * $10 = $30.
Carlos had 6x amount of money, which is 6 * $10 = $60.

So, Carlos received $60, and Simon received $10.