Posted by tony on .
Find all values of ¸ in [0°, 360°) that satisfy the equation.
2 sin 2θ  √(3) = 0

trig 
Steve,
2sin2θ = √3
sin2θ = √3/2
sin(x) is positive in QI,QII
2θ = 60°,120°,...
we need to go for two periods because we're dealing with 2θ. That gives us
θ = 30°,60°,210°,240°