Monday

July 28, 2014

July 28, 2014

Posted by **AAA** on Monday, June 17, 2013 at 3:29am.

(The battery is parallel with a inductor with a resitance in serie and is parallel with a capacitor in serie with a resistance).

Initially, the switch S is open as in the figure above and there is no charge on the capacitor C and no current flowing through the inductor L. At t=0 we close the switch.

Define the current through the inductor to be positive if it flows through the inductor and then through the resistor and therefore down in the drawing. Similarly, define the current through the capacitor to be positive if it flows down in the drawing.

What is the current through the inductor (in Amps) at t=0 (i.e. just after the switch is closed)?

Initially, the switch S is open as in the figure above and there is no charge on the capacitor C and no current flowing through the inductor L. At t=0 we close the switch.

Define the current through the inductor to be positive if it flows through the inductor and then through the resistor and therefore down in the drawing. Similarly, define the current through the capacitor to be positive if it flows down in the drawing.

What is the current through the inductor (in Amps) at t=0 (i.e. just after the switch is closed)?Initially, the switch S is open as in the figure above and there is no charge on the capacitor C and no current flowing through the inductor L. At t=0 we close the switch.

Define the current through the inductor to be positive if it flows through the inductor and then through the resistor and therefore down in the drawing. Similarly, define the current through the capacitor to be positive if it flows down in the drawing.

What is the current through the inductor (in Amps) at t=0 (i.e. just after the switch is closed)?Initially, the switch S is open as in the figure above and there is no charge on the capacitor C and no current flowing through the inductor L. At t=0 we close the switch.

Define the current through the inductor to be positive if it flows through the inductor and then through the resistor and therefore down in the drawing. Similarly, define the current through the capacitor to be positive if it flows down in the drawing.

What is the current through the inductor (in Amps) at t=0 (i.e. just after the switch is closed)?

What is the current through the inductor (in Amps) at t=8.70e-4 s?

What is the current through the inductor (in Amps) a long time later?

What is the current through the capacitor (in Amps) at t=0 (i.e. just after the switch is closed)?

What is the current through the capacitor (in Amps) at t=2.07e-4 s?

What is the current through the capacitor (in Amps) a long time later?

- Physics -
**Jorsh**, Monday, June 17, 2013 at 9:29ama)0

b)---

c)V/R=5/11

d)V/R=5/11

e)(v/R)*exp(-t/(R*C)=(5/11)*exp(-t/(11*2e-6)

f)0

help me in

5a,9,10,11

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