Posted by jack on Sunday, June 16, 2013 at 7:32pm.
find equation of tangent line for x^(1/3) + y^(1/2)=2 at point (1,1)

answer only  can not post derivation  Damon, Sunday, June 16, 2013 at 7:53pm
Once again I can not post my answer but in the end I get
3 y = 2 x + 5 
screaming frustration  Damon, Sunday, June 16, 2013 at 7:54pm
Can other teachers post all right ?

Trying again  Damon, Sunday, June 16, 2013 at 7:56pm
no luck  hope someone can help you.
the idea is to do f(d+dx)  f(x)
where f(x+dx) = f(x) + (dy/dx) dx 
calculus  Ms. Sue, Sunday, June 16, 2013 at 7:58pm
I've sent your posts to Bob and Leo. I'll send this one too.

Thanks  Damon, Sunday, June 16, 2013 at 7:59pm
Thanks  I can not really answer this because it will not let me write out derivative method.

calculus  Writeacher, Sunday, June 16, 2013 at 8:00pm
Bob knows. He has cleaned out the banned list, and said he'd check more specifically later.
I've texted Leo ... I'm surprised there's been no answer.
=( 
calculus  Reiny, Sunday, June 16, 2013 at 9:27pm
(1/3)x^(2/3) + (1/2)y^(1/2) dy/dx = 0
at (1,1)
(1/3)(1) + (1/2)(1)dy/dx =0
dy/dx =(1/2) / (1/3) = 3/2
so y1 = (3/2)(x1)
2y  2 = 3x + 3
2y = 3x + 5
y = (3/2)x + 5/2
Damon, I had the same problem, now it seems to work 
calculus  Damon, Monday, June 17, 2013 at 9:39am
tangent line for x^(1/3) + y^(1/2)=2 at point (1,1)

(1/3) / x^(2/3) + (1/2) dy/dx /y^(1/2)=0
so
(1/2)dy/dx = (1/3) y^(1/2)/x^(2/3)
at (1.1)
dy/dx = (2/3)
then
y = 2x/3 + b
1 = 2/3 + b
b = 5/3
so
y = 2x/3 + 5/3
3 y = 2 x + 5