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calculus

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estimate change in f using the linear approximation and compute both error and the % error

f(x)= (3+x)^1/2

a=1

change in x=0.5

  • calculus - ,

    estimate ln(e^2+0.1)-ln(e^2)

  • calculus - ,

    f(x) = ln x
    df = (df/dx) dx

    df = (1/x) dx

    f(x+dx) = f(x) + (df/dx) dx

    f( e^2 + 0.1) = ln(e^2) + (1/e^2)(0.1)

    f(e^2 +0.1) - ln(e^2) = 0.1/e^2

    = .0135335

  • Now I can use my name but not copy - ,

    no copy and paste for me any more I guess.

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