Posted by jack on Sunday, June 16, 2013 at 6:39pm.
estimate change in f using the linear approximation and compute both error and the % error
f(x)= (3+x)^1/2
a=1
change in x=0.5

calculus  jack, Sunday, June 16, 2013 at 6:50pm
estimate ln(e^2+0.1)ln(e^2)

calculus  Damon, Sunday, June 16, 2013 at 7:43pm
f(x) = ln x
df = (df/dx) dx
df = (1/x) dx
f(x+dx) = f(x) + (df/dx) dx
f( e^2 + 0.1) = ln(e^2) + (1/e^2)(0.1)
f(e^2 +0.1)  ln(e^2) = 0.1/e^2
= .0135335

Now I can use my name but not copy  Damon, Sunday, June 16, 2013 at 7:43pm
no copy and paste for me any more I guess.
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