calculus
posted by jack on .
estimate change in f using the linear approximation and compute both error and the % error
f(x)= (3+x)^1/2
a=1
change in x=0.5

estimate ln(e^2+0.1)ln(e^2)

f(x) = ln x
df = (df/dx) dx
df = (1/x) dx
f(x+dx) = f(x) + (df/dx) dx
f( e^2 + 0.1) = ln(e^2) + (1/e^2)(0.1)
f(e^2 +0.1)  ln(e^2) = 0.1/e^2
= .0135335 
no copy and paste for me any more I guess.