Posted by jack on .
estimate change in f using the linear approximation and compute both error and the % error
change in x=0.5
f(x) = ln x
df = (df/dx) dx
df = (1/x) dx
f(x+dx) = f(x) + (df/dx) dx
f( e^2 + 0.1) = ln(e^2) + (1/e^2)(0.1)
f(e^2 +0.1) - ln(e^2) = 0.1/e^2
Now I can use my name but not copy -
no copy and paste for me any more I guess.