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October 1, 2014

October 1, 2014

Posted by **jack** on Sunday, June 16, 2013 at 6:39pm.

f(x)= (3+x)^1/2

a=1

change in x=0.5

- calculus -
**jack**, Sunday, June 16, 2013 at 6:50pmestimate ln(e^2+0.1)-ln(e^2)

- calculus -
**Damon**, Sunday, June 16, 2013 at 7:43pmf(x) = ln x

df = (df/dx) dx

df = (1/x) dx

f(x+dx) = f(x) + (df/dx) dx

f( e^2 + 0.1) = ln(e^2) + (1/e^2)(0.1)

f(e^2 +0.1) - ln(e^2) = 0.1/e^2

= .0135335

- Now I can use my name but not copy -
**Damon**, Sunday, June 16, 2013 at 7:43pmno copy and paste for me any more I guess.

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