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February 1, 2015

February 1, 2015

Posted by **Tony** on Sunday, June 16, 2013 at 11:43am.

- Trigonometry -
**Steve**, Sunday, June 16, 2013 at 3:29pmb/sinB = a/sinA = c/sinC

sinA/a = sinC/C

sinA = a/c sinC

sinA+sinC = (1+a/c) sinC

= (a+c)/c sinC

2sinB = sinA+sinC = 70/c sinC

2b/2sinB = c/sinC

2b = (70/c) sinC * c/sinC

= 70

b = 35

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