Posted by **jennath** on Sunday, June 16, 2013 at 11:04am.

300 is divided into 2 parts so that half of one part may be less than other by 48.then the parts are?find the linear equation

- matha school.alleppey -
**kaveri**, Saturday, November 28, 2015 at 12:56am
Solution: Let x + y = 300, where x and y are two (parts)numbers

Given, x - y/2 = 48

=> x = 48 + y/2

Hence, 48 + y/2 + y = 300

3y/2 = 252

y = 2 X 252 / 3 = 504 / 3 = 168

x = 300 - 168 = 132

Hence, the two parts (numbers)are 132 and 168.

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