300 is divided into 2 parts so that half of one part may be less than other by 48.then the parts are?find the linear equation
Solution: Let x + y = 300, where x and y are two (parts)numbers
Given, x - y/2 = 48
=> x = 48 + y/2
Hence, 48 + y/2 + y = 300
3y/2 = 252
y = 2 X 252 / 3 = 504 / 3 = 168
x = 300 - 168 = 132
Hence, the two parts (numbers)are 132 and 168.
168 And 132
Brilliant 🙂🙂🙂
To find the two parts when 300 is divided, let's assume the smaller part as 'x' and the larger part as 'y'.
According to the problem statement, we know that half of one part is less than the other part by 48. Mathematically, we can represent this as:
y - (x/2) = 48
Rearranging the equation, we get:
2y - x = 96
Since we have a system of equations, we need to find additional information to solve it.
Good
Let x+y=300,where x and yare two parts
Given,x-y/2 =48
=>x=48+y/2