matha school.alleppey
posted by jennath on .
300 is divided into 2 parts so that half of one part may be less than other by 48.then the parts are?find the linear equation

Solution: Let x + y = 300, where x and y are two (parts)numbers
Given, x  y/2 = 48
=> x = 48 + y/2
Hence, 48 + y/2 + y = 300
3y/2 = 252
y = 2 X 252 / 3 = 504 / 3 = 168
x = 300  168 = 132
Hence, the two parts (numbers)are 132 and 168. 
168 And 132