Posted by anonymous on .
a body moves for a total of 9 seconds starting from rest with uniform acceleration and then with uniform retardation which is twice of value of acceleration to stop .what is the duration of uniform acceleration

Physics 11th 
Anonymous,
v=u+at

Physics 11th 
Pritam singh,
Distance covered in 4 secods after tha 5th seconds= S9 s5 .tha distance covered in t second is given by s = ut 1/2 at2and distance covered in nth second is given by Dn = u a/2 (2n1)

Physics 11th 
Pritam singh,
Distance covered in 4 secods after tha 5th seconds= S9 s5 .tha distance covered in t second is given by s = ut 1/2 at2and distance covered in nth second is given by Dn = u a/2 (2n1) The modern sr. sec. Bagpur palwal phone no. 8059892363

Physics 11th 
Genius,
Use v=u+at and form two equations one for acc. And one for retard. Then on solving u will get d ans. I hope dat helps.. 😀 ☺