Posted by anonymous on Sunday, June 16, 2013 at 9:14am.
a body moves for a total of 9 seconds starting from rest with uniform acceleration and then with uniform retardation which is twice of value of acceleration to stop .what is the duration of uniform acceleration

Physics 11th  Anonymous, Sunday, August 24, 2014 at 2:07am
v=u+at

Physics 11th  Pritam singh, Friday, August 29, 2014 at 8:16am
Distance covered in 4 secods after tha 5th seconds= S9 s5 .tha distance covered in t second is given by s = ut 1/2 at2and distance covered in nth second is given by Dn = u a/2 (2n1)

Physics 11th  Pritam singh, Friday, August 29, 2014 at 8:18am
Distance covered in 4 secods after tha 5th seconds= S9 s5 .tha distance covered in t second is given by s = ut 1/2 at2and distance covered in nth second is given by Dn = u a/2 (2n1) The modern sr. sec. Bagpur palwal phone no. 8059892363

Physics 11th  Genius, Wednesday, June 10, 2015 at 3:41am
Use v=u+at and form two equations one for acc. And one for retard. Then on solving u will get d ans. I hope dat helps.. 😀 ☺
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