Physics 11th
posted by anonymous .
a body moves for a total of 9 seconds starting from rest with uniform acceleration and then with uniform retardation which is twice of value of acceleration to stop .what is the duration of uniform acceleration

v=u+at

Distance covered in 4 secods after tha 5th seconds= S9 s5 .tha distance covered in t second is given by s = ut 1/2 at2and distance covered in nth second is given by Dn = u a/2 (2n1)

Distance covered in 4 secods after tha 5th seconds= S9 s5 .tha distance covered in t second is given by s = ut 1/2 at2and distance covered in nth second is given by Dn = u a/2 (2n1) The modern sr. sec. Bagpur palwal phone no. 8059892363

Use v=u+at and form two equations one for acc. And one for retard. Then on solving u will get d ans. I hope dat helps.. 😀 ☺