4l of water is added to 2L of 6M HCL.What is the molarity of the final solution
To find the molarity of the final solution, you will need to use the formula:
M1V1 = M2V2
Where:
M1 = Initial molarity of the first solution
V1 = Initial volume of the first solution
M2 = Final molarity of the solution
V2 = Final volume of the solution
Given values:
M1 = 6M
V1 = 2L
V2 = 2L + 4L = 6L
Now, let's substitute the values into the formula and solve for M2:
6M * 2L = M2 * 6L
12 = M2 * 6
Divide both sides by 6:
12 / 6 = M2
M2 = 2M
Therefore, the molarity of the final solution is 2M.
To find the molarity of the final solution, we need to use the formula:
M1V1 = M2V2
where:
M1 = initial molarity
V1 = initial volume
M2 = final molarity
V2 = final volume
In this case, the initial molarity is 6M and the initial volume is 2L. We add 4L of water to get the final volume.
So, let's plug in the values into the formula:
(6M)(2L) = M2(2L + 4L)
12 = M2(6L)
To find M2, we need to isolate it, so divide both sides of the equation by 6L:
12 / 6L = M2
Simplifying, we get:
2M = M2
Therefore, the molarity of the final solution is 2M.