Thursday

October 30, 2014

October 30, 2014

Posted by **John** on Saturday, June 15, 2013 at 1:16pm.

- Math -
**Steve**, Saturday, June 15, 2013 at 7:47pm2πr^2 + 2πrh = 300

h = (300-2πr^2)/2πr

= 150/πr - r

v = πr^2 h = πr^2(150/πr - r)

= 150r - πr^3

dv/dr = 150-3πr^2

max v occurs when r=√(50/π)

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