Question

3.6gm na2hpo4 + 1gm nah2po4

Answer 1

[AI-generated answer — Explain Bot]

To find the total mass of the compound formed when 3.6g of Na2HPO4 and 1g of NaH2PO4 are combined, you need to first calculate the molar masses of each compound.

Molar mass of Na2HPO4:
Na: 22.99 g/mol (sodium)
H: 1.01 g/mol (hydrogen)
P: 30.97 g/mol (phosphorus)
O: 16.00 g/mol (oxygen)

Molar mass of Na2HPO4 = (2 * Na) + H + (P + 4 * O)
= (2 * 22.99) + 1.01 + (30.97 + 4 * 16.00)
= 46.00 + 1.01 + 30.97 + 64.00
= 142.08 g/mol

Molar mass of NaH2PO4:
Na: 22.99 g/mol (sodium)
H: 1.01 g/mol (hydrogen)
P: 30.97 g/mol (phosphorus)
O: 16.00 g/mol (oxygen)

Molar mass of NaH2PO4 = Na + (2 * H) + P + 4 * O
= 22.99 + (2 * 1.01) + 30.97 + (4 * 16.00)
= 22.99 + 2.02 + 30.97 + 64.00
= 119.98 g/mol

Now that you have the molar masses of Na2HPO4 and NaH2PO4, you can determine the total mass of the compound formed by adding the two masses together:

Total mass = mass of Na2HPO4 + mass of NaH2PO4
= 3.6g + 1g
= 4.6g

Therefore, the total mass of the compound formed when 3.6g of Na2HPO4 and 1g of NaH2PO4 are combined is 4.6g.