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April 16, 2014

April 16, 2014

Posted by **urgent answer needed** on Saturday, June 15, 2013 at 4:43am.

Details and assumptions

You may take the acceleration of gravity as −9.8 m/s2.

You may neglect air resistance.

- physics -
**MathMate**, Saturday, June 15, 2013 at 7:29amAcceleration phase:

initial velocity, v0 = 0 m/s

final velocity, v1 = at = 8*20 = 160 m/s

distance, S = ut+(1/2)at² = 0 + (1/2)8(20²)

=(1/2)8(400)=1600 m

Free fall phase:

v0 = 160 m/s

acceleration,a = -9.8 m/s²

v0 = 160 m/s

v1 = 0

a = g =-9.8 m/s²

use

v1²-v0²=2aS

to solve for S, distance.

Add this to the 1600 m in the acceleration phase to get the maximum height.

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