Posted by urgent answer needed on Saturday, June 15, 2013 at 4:43am.
A rocket accelerates straight up from rest for 20 seconds with an acceleration of 8 m/s2. After 20 seconds the rocket motor shuts off and the rocket continues to coast upwards. How high does the rocket go in meters?
Details and assumptions
You may take the acceleration of gravity as −9.8 m/s2.
You may neglect air resistance.

physics  MathMate, Saturday, June 15, 2013 at 7:29am
Acceleration phase:
initial velocity, v0 = 0 m/s
final velocity, v1 = at = 8*20 = 160 m/s
distance, S = ut+(1/2)at² = 0 + (1/2)8(20²)
=(1/2)8(400)=1600 m
Free fall phase:
v0 = 160 m/s
acceleration,a = 9.8 m/s²
v0 = 160 m/s
v1 = 0
a = g =9.8 m/s²
use
v1²v0²=2aS
to solve for S, distance.
Add this to the 1600 m in the acceleration phase to get the maximum height.

physics  steve, Friday, October 2, 2015 at 1:37pm
ewywer
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