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What volume of 0.123 M NaOH(aq) must be added to 125 mL of 0.197 M H2SO3(aq) to reach the following points?

(a) the first stoichiometric point
(b) the second stoichiometric point

  • Chemistry -

    H2SO3 + 2NaOH ==> Na2SO3 + 2H2O
    mols H2SO3 = M x L = ?
    mols NaOH = 2 times mols H2SO3
    It takes that many mols NaOH to neutralize BOTH H ions of H2SO3.
    Then mols NaOH = M x L; you know mols NasOH and M, solve for L NaOH.

    Take half that volume to find L for the first stoichiometric point.

  • Chemistry -

    moles of H2SO3 = 0.0246
    moles of 2NaOH = 0.04925

    Second stiochiometric point volume: 400. mL
    First stiochiometric point volume: 200. mL


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