Posted by Isis on Friday, June 14, 2013 at 9:45am.
An object is thrown directly up (positive direction) with a velocity (vo) of 20.0 m/s and do= 0. Determine how long it takes to get to the maximum height of 24.0 m.

Physics  Chan, Friday, June 14, 2013 at 9:59am
I don't get what d0 means. Explain properly

Physics  Isis, Friday, June 14, 2013 at 10:05am
Displacement with Constant Acceleration.This equation may be used to find the displacement of any object moving with constant acceleration. that's what it says

Physics  Elena, Friday, June 14, 2013 at 1:01pm
initial position d₀=0,
The maximum height at the motion with initial velocity v₀=20 m/s
is
H=v₀²/2g=20²/2•9.8 = 20.4 m (!!!)
H=v₀tgt²/2,
v(fin)= v₀ gt,
v(fin)=0, =>
0= v₀ gt =>
v₀ =gt,
H=gt²gt²/2= gt²/2,
t=sqrt{2H/g}=sqrt(2•20.4/9.8)=2.04 s
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