Posted by **Isis** on Friday, June 14, 2013 at 9:45am.

An object is thrown directly up (positive direction) with a velocity (vo) of 20.0 m/s and do= 0. Determine how long it takes to get to the maximum height of 24.0 m.

- Physics -
**Chan**, Friday, June 14, 2013 at 9:59am
I don't get what d0 means. Explain properly

- Physics -
**Isis**, Friday, June 14, 2013 at 10:05am
Displacement with Constant Acceleration.This equation may be used to find the displacement of any object moving with constant acceleration. that's what it says

- Physics -
**Elena**, Friday, June 14, 2013 at 1:01pm
initial position d₀=0,

The maximum height at the motion with initial velocity v₀=20 m/s

is

H=v₀²/2g=20²/2•9.8 = 20.4 m (!!!)

H=v₀t-gt²/2,

v(fin)= v₀ -gt,

v(fin)=0, =>

0= v₀ -gt =>

v₀ =gt,

H=gt²-gt²/2= gt²/2,

t=sqrt{2H/g}=sqrt(2•20.4/9.8)=2.04 s

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