Posted by **Ashley** on Friday, June 14, 2013 at 4:41am.

Please please help!!!!!

Solve the inequality and write the solution set in interval notation

4x^3 -6x^2<0

2x^2 (2x-3)<0

2x-3<0

x= 3/2

Now I'm not sure about this

2x^2<0

x^2<1/2

sq root of x^2<sq root of 1/2

x=.7071

Right?

When I plug it in the calculator it says

X=0

How?

- Math -
**Steve**, Saturday, June 15, 2013 at 12:16am
4x^3 - 6x^2 < 0

2x^2 (2x-3) < 0

You should know the general shape of this graph. It has a double root at x=0 and it crosses the x-axis at x=3/2.

So, the graph is below the x-axis for all values of x less than 3/2, except x=0.

2x-3 < 0 is an inequality.

You cannot change it to an equation: x = 3/2

2x-3 < 0

2x < 3

x < 3/2

--------------------------------------

If 2x^2 < 0

you cannot say x^2 < 1/2

0/2 = 0

HINT: x^2 is always >=0, so 2x^2 is always >= 0.

Always

(a) check your answer in the original expression

(b) THINK about your answer in teh context of the problem!

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