Posted by Ant on .
Find an equation of the tangent line to the graph of the function f defined by the following equation at the indicated point.
(x  y  1)3 = x; (1, 1)
y =

Calculus 
Steve,
y+1 = 1/f'(1) (x1)
3(xy1)^2 (1y') = 1
at (1,1)
3(1y') = 1
y' = 4/3