Posted by **Jana** on Thursday, June 13, 2013 at 8:46pm.

The probability of a randomly selected car crashing during a year in a certain country is .0479. If a family has three cars, find the probability that at least one of them has a car crash during a year.

- Statistics -
**jiya**, Thursday, June 13, 2013 at 10:47pm
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- Statistics -
**PsyDAG**, Friday, June 14, 2013 at 1:19pm
"At least one" = either 1, 2 or 3.

If the events are independent, the probability of both/all events occurring is determined by multiplying the probabilities of the individual events.

for 1: .0479 * (1-.0479)^2 = ?

for 2: .0479^2 * (1-.0479) = ?

for 3: .0479^3 = ?

Either-or probabilities are found by adding the individual probabilities.

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