If 16<square root x <25, then what two integers is x between?

please help me solve with a step by step method so I can get this.

thanks for your time and help

16 < √x < 25

256 < x < 625

just realized it's that easy!!!!!

To find the two integers that x is between when given the inequality 16 < √x < 25, we need to square both sides of the inequality to eliminate the square root.

Step 1: Square the lower limit:
16 < √x
Square both sides of the inequality:
(16)^2 < (√x)^2
256 < x

Step 2: Square the upper limit:
√x < 25
Square both sides of the inequality:
(√x)^2 < (25)^2
x < 625

So, we know that x is greater than 256 and less than 625.

Now, we need to find the two integers between these limits. We start by finding the largest integer that is less than the upper limit (625) and the smallest integer that is greater than the lower limit (256).

Step 3: Find the largest integer less than 625:
The largest integer less than 625 is 624.

Step 4: Find the smallest integer greater than 256:
The smallest integer greater than 256 is 257.

Therefore, x is between the integers 257 and 624.