posted by Adam on .
A resistive load of 2 k is connected across the secondary windings of a 25:1 transformer. If the primary voltage is 50 V AC, what will be the secondary current?
im getting 2mA but the correct answer is 1 mA please help
Z1 = (25)^2 * 2x = 1250k Ohms
I1 = 50/1250k = 0.04 mA..