Post a New Question


posted by on .

A resistive load of 2 k is connected across the secondary windings of a 25:1 transformer. If the primary voltage is 50 V AC, what will be the secondary current?

im getting 2mA but the correct answer is 1 mA please help

  • transformers - ,

    Z1 = (25)^2 * 2x = 1250k Ohms
    I1 = 50/1250k = 0.04 mA..


Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question