Posted by **Anonymous** on Sunday, June 9, 2013 at 12:44am.

Consider the following 6 relations on the set of real numbers:

A) y=2x−5,

B) x2+y2=1,

C) x=20−2y,

D) y=10−x2−−−−−−√,

E) y=2x2−3x+4 and

F) y=|x|

How many of these relations define y as a function of x in the domain −10≤x≤10?

- math -
**Reiny**, Sunday, June 9, 2013 at 8:34am
A , C, and F are linear, thus defined for all x's

B)

x^2 + y^2 = 1 is a circle , thus not a function, which is only defined for -1 ≤ x ≤ +1

E) a quadratic function, defined for all x's

D) not sure what you meant here

if it is y = √(10-2x)

then it would be defined only for

10 - 2x ≥ 0

-2x ≥ -10

x ≤ 5

so no, not defined for all of -10 ≤ x ≤ 10

So all would be except B and D

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