Post a New Question

math

posted by on .

Consider the following 6 relations on the set of real numbers:

A) y=2x−5,

B) x2+y2=1,

C) x=20−2y,

D) y=10−x2−−−−−−√,

E) y=2x2−3x+4 and

F) y=|x|
How many of these relations define y as a function of x in the domain −10≤x≤10?

  • math - ,

    A , C, and F are linear, thus defined for all x's

    B)
    x^2 + y^2 = 1 is a circle , thus not a function, which is only defined for -1 ≤ x ≤ +1

    E) a quadratic function, defined for all x's

    D) not sure what you meant here
    if it is y = √(10-2x)
    then it would be defined only for
    10 - 2x ≥ 0
    -2x ≥ -10
    x ≤ 5
    so no, not defined for all of -10 ≤ x ≤ 10

    So all would be except B and D

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question