Posted by **Anonymous** on Sunday, June 9, 2013 at 12:44am.

Consider the following 6 relations on the set of real numbers:

A) y=2x−5,

B) x2+y2=1,

C) x=20−2y,

D) y=10−x2−−−−−−√,

E) y=2x2−3x+4 and

F) y=|x|

How many of these relations define y as a function of x in the domain −10≤x≤10?

- math -
**Reiny**, Sunday, June 9, 2013 at 8:34am
A , C, and F are linear, thus defined for all x's

B)

x^2 + y^2 = 1 is a circle , thus not a function, which is only defined for -1 ≤ x ≤ +1

E) a quadratic function, defined for all x's

D) not sure what you meant here

if it is y = √(10-2x)

then it would be defined only for

10 - 2x ≥ 0

-2x ≥ -10

x ≤ 5

so no, not defined for all of -10 ≤ x ≤ 10

So all would be except B and D

## Answer This Question

## Related Questions

- biology - Given the part of the molecule shown below, can the underlined atom ...
- Grade 12 Calculus - Evaluate each of the following. Show all your calculations...
- calculus (gr 12) - Evaluate each of the following. Show all your calculations. a...
- calculus (gr 12) - Evaluate each of the following. Show all your calculations. a...
- calculus - Find an equation for the surface consisting of all points P(x, y, z) ...
- math - The number 27+200−−−√−−−−...
- physics - Four charges −8 × 10^−9 C at (0 m, 0 m), −7 × 10^&#...
- MATHS - The number 2+3√+5√−−−−−−...
- math help azap - Select all of the expressions that are equivalent to 1/3(−...
- chemistry - For which of these elements would the electron affinity process ...

More Related Questions