Posted by **Hello** on Saturday, June 8, 2013 at 10:49pm.

In which quadrant is the terminal side of angle A?

A = -5π/6

a. Quadrant III

b. Quadrant I

c. Quadrant II

d. Quadrant IV

- Math Trig Find Quadrant I II III IV -
**Reiny**, Saturday, June 8, 2013 at 11:18pm
Think of degrees if radians give you trouble

π radians = 180°

so (-5/6)π radians = -(5/6)(180)° = -150°

so going clockwise 150° would put you into quadrant III

- Math Trig Find Quadrant I II III IV -
**Fred**, Wednesday, August 19, 2015 at 5:33am
Hello, i cant find out the values of x1,x2 can u help me please?

sinx=2sinx+1

0=sinx+1

sinx=-1 <0 (III;IV)

sinx=270*

x1= ?

x2= ?

- Math Trig Find Quadrant I II III IV -
**Ellen**, Sunday, October 11, 2015 at 10:59am
to Fred:

sinx=2sinx+1

0=2sinx+1-sinx

0=sinx+1

sinx=-1

We are going to look for the values of x.

sin is < 0 meaning, the values are either in quadrant III/ IV.

First, identify the rad equivalent where sin equates to -1.

And that would be 270 degrees or 3pi/2 located at the 3rd quadrant.

3rd quadrant (check!)

4th quadrant (?)

The range for the 3rd quadrant is 180-270 degrees, and the range of for 4th quadrant is from 270-360 degrees.

if you have a limit such as the values are only within [0, 2pi] then you only need 3pi/2 since its within the 3rd and 4th quadrant.

x1= 3pi/2. x2= 3pi/2.

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