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August 29, 2014

August 29, 2014

Posted by **Sharday** on Saturday, June 8, 2013 at 10:29pm.

f(x)=x^3-4x^2-19x-14

- algebra -
**Anonymous**, Saturday, June 8, 2013 at 10:55pm-2, -1, 7

- algebra -
**Reiny**, Saturday, June 8, 2013 at 11:09pmtry x = ±1, ±2, and ± 7

f(1) = 1 - 4 - 19 - 14 ≠ 0

f(-1) = -1 - 4 + 19 - 14 = 0

ahhh, so (x+1) is a factor

using algebraic division

x^3-4x^2-19x-14 = 0

(x+1)(x+2)(x-7) = 0

so x = -1, -2 or 7

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