What is the factor of safety of a steel hanger having an ultimate strength of 550.000MPa and supporting a load of 64000.000N. The steel hanger in question has a cross sectional area of 7.600cm^2.

Answer = (Round to 3 decimal places)

To find the factor of safety of a steel hanger, we need to compare the actual stress experienced by the hanger to the maximum allowable stress it can withstand.

First, let's calculate the stress on the steel hanger. Stress is defined as the force applied per unit area. The formula for stress is:

Stress = Force / Area

We are given:
Force = 64,000 N
Area = 7.600 cm^2 = 7.600 x 10^-4 m^2 (since 1 cm^2 = 10^-4 m^2)

Substituting these values into the formula, we get:
Stress = 64,000 N / 7.600 x 10^-4 m^2

Next, let's calculate the maximum allowable stress. The maximum allowable stress is determined by the ultimate strength of the material. In this case, the ultimate strength is given as 550,000 MPa (MegaPascals). To convert MegaPascals to Pascals, we multiply by 10^6.

Maximum Allowable Stress = 550,000 MPa x 10^6 Pa/MPa

Now, we divide the stress on the steel hanger by the maximum allowable stress to obtain the factor of safety.

Factor of Safety = Stress / Maximum Allowable Stress

Let's plug in the values:

Stress = 64,000 N / 7.600 x 10^-4 m^2
Maximum Allowable Stress = 550,000 MPa x 10^6 Pa/MPa

Using a calculator, we can evaluate these expressions and find the factor of safety. Rounding the result to 3 decimal places gives us the final answer.