Thursday
August 21, 2014

Homework Help: Chemistry- Dr Bob

Posted by Steve on Friday, June 7, 2013 at 10:55pm.

Dr Bob

Can you please assist
Redox balancing in BASIC sol.
NO2- +Al-->NH3 +Al(OH)4-

if you could please walk thru step by step.

I dont know how to get oxidation #s for Al(OH)4- vs. Al

I get Al=0
Al(OH)4-= +3

But if so...then my oxidation half reaction is
Al-->Al(OH)4- + 3e-

Nitrogen reduction half rxn has no electron inbalance

Just not sure how the answer is this:

NO2- +2Al +5H2O +OH--->NH3+2Al(OH)4-

No idea how coefficient on Al went to (2)???

No clue where 5 waters come from?

I think there is something about how the OH subscript 4 ^- is dealt with.

Sorry so confusing.

Thanks!

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