Thursday

July 24, 2014

July 24, 2014

Posted by **Steven** on Friday, June 7, 2013 at 9:57pm.

$(x-2)^n/(2x+1)

I did the ratio test and ended up with:

absolute value[(x-2)/(2x+1)]<1

How would I solve for the inequality at this point?

- Calculus -
**Steve**, Saturday, June 8, 2013 at 4:56pmIf |(x-2)/(2x+1)| < 1 then

(x-2)^2 < (2x+1)^2

x^2 - 4x + 4 < 4x^2 + 4x + 1

3x^2 + 8x - 3 > 0

x < -3 or x > 1/3

**Related Questions**

Calculus - How do I find the radius of convergence of a series where n=1 to ...

CALC - please help me...for the power series summation of n^4x^n/2(n-1)factorial...

Calculus - What is the radius of convergence of the power series (((2n)!x^(n...

math quick question - Hi! Thank you for your help~~ What is the absolute value ...

Calculus - please help me...for the power series summation of n^4x^n/2(n-1)...

calculus - in the following series x is a real number. In each case use the ...

CALCULUS - find the radius and interval of convergence for the series the series...

CALCULUS-URGENT - find the radius and interval of convergence for the series the...

CALCULUS-URGENT- no one will respond!!! - find the radius and interval of ...

Calculus - If you have a geometric alternating series, and you prove that the ...