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April 20, 2014

April 20, 2014

Posted by **Steven** on Friday, June 7, 2013 at 9:57pm.

$(x-2)^n/(2x+1)

I did the ratio test and ended up with:

absolute value[(x-2)/(2x+1)]<1

How would I solve for the inequality at this point?

- Calculus -
**Steve**, Saturday, June 8, 2013 at 4:56pmIf |(x-2)/(2x+1)| < 1 then

(x-2)^2 < (2x+1)^2

x^2 - 4x + 4 < 4x^2 + 4x + 1

3x^2 + 8x - 3 > 0

x < -3 or x > 1/3

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