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December 20, 2014

December 20, 2014

Posted by **Tee** on Friday, June 7, 2013 at 2:44pm.

f(x) = x^2 - x + 1 text( on ) [-1,12]; M = 21

- Calculus -
**Steve**, Friday, June 7, 2013 at 2:51pmFirst, check to be sure that M is in the range of f over the interval:

f(-1) = 3

f(12) = 133

so 21 is in the range.

Since f is continuous, and changes from 3 to 133, it must attain the value of 21 somewhere in there. That is, there is some c such that

f(x) = 21

To find c, just solve the equation

x^2-x+1 = 21

x^2-x-20 = 0

(x-5)(x+4) = 0

x = -4,5

SO, f(5) = 21 and 5 is in [-1,12]

f(-4) = 21 too, but it's outside the interval of interest.

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