A car starts 200 m west of the town square and moves with a constant velocity of 15 m/s toward the east.
a.Write the equation that represents the motion of the car.
b.Where will the car be 10 minutes later?
c.When will the car reach the town square?
Ok so I’m not going to do the whole question over again but here’s what I have:
(200m) / (15m/s) = 13.33333 sec
As far as where the car is after 10mins, my ANSWER KEY says *8800m* but I seem to keep getting 9000m.
Ex. (Vi + Vf) t
/2
[excuse my inability to format this, and I’m too lazy to put in units]
First, 10min = 600sec (t)
(15+15)= 30
30/2 = 15
15 x 600 = 9000m
But whatever lol. I hope this helped in some way.
I just wanted to add onto what Kat said- I also kept getting 9000, but since you start at -200m, I subtracted 200m from the 9000m to get the 8800m. I think that's how you're supposed to do it. :)
a. The equation that represents the motion of the car can be written as:
Distance (d) = Initial distance + Velocity × Time
In this case, the initial distance is 200 m west of the town square, the velocity is 15 m/s towards the east, and the time is t (in seconds). So the equation would be:
d = -200 + 15t (where the negative sign indicates west direction)
b. To find where the car will be 10 minutes later, we need to convert the time to seconds first. Since there are 60 seconds in a minute, 10 minutes would be equal to 10 × 60 = 600 seconds.
Plugging this value into the equation:
d = -200 + 15 × 600
d = -200 + 9000
d = 8800
So the car will be 8800 meters east of the town square 10 minutes later.
c. To find when the car will reach the town square, we need to find the time (t) when the distance (d) is equal to 0.
0 = -200 + 15t
Solving for t:
15t = 200
t = 200 / 15
t ≈ 13.33 seconds
So the car will reach the town square approximately 13.33 seconds after it starts moving.
a. To represent the motion of the car, we can use the equation:
Position = Initial position + Velocity * Time
In this case, the initial position of the car is 200 m west of the town square, so the initial position is -200 m (negative because it is west of the town square). The velocity of the car is 15 m/s toward the east (positive speed eastward), so the velocity is +15 m/s.
Therefore, the equation representing the motion of the car is:
Position = -200 + 15 * Time
b. To find where the car will be 10 minutes later, we need to substitute the value of time, which is 10 minutes, into the equation.
First, we need to convert 10 minutes to seconds since the velocity is given in meters per second. There are 60 seconds in 1 minute, so 10 minutes is equal to 10 * 60 = 600 seconds.
Now, we can use the equation from part a to find the position:
Position = -200 + 15 * 600 = 8600 m
Therefore, the car will be 8600 meters east of the town square 10 minutes later.
c. To find when the car will reach the town square, we need to set the position equal to zero and solve for time.
0 = -200 + 15 * Time
Let's solve for Time:
200 = 15 * Time
Time = 200 / 15 = 13.33 seconds
Therefore, the car will reach the town square approximately 13.33 seconds after it starts moving.
if the town square is at x = 0 and east is positive then:
x = -200 + 15 t
in ten minutes x = -200 + 150 = -50 or 50 meters west of the square
when is x = 0?
0 = -200 + 15 t
t = 200/15 = 13 1/3 seconds to the square