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November 26, 2014

November 26, 2014

Posted by **Jean Claude** on Friday, June 7, 2013 at 12:24am.

(a) P(two of diamonds)

1

(b) P(two)

2

(c) P(diamond)

3

- math -
**PsyDAG**, Friday, June 7, 2013 at 12:41pma) There is only one two of diamonds in the deck, therefore 1/52.

Use a similar process for the remaining two problems.

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