Post a New Question


posted by .

Use Green's theorem to evaluate the integral:
y^(2)dx+xy dy
where C is the boundary of the region lying between the graphs of y=0,
y=sqrt(x), and x=9

  • Calculus -

    Using the definition, we have
    P = y^2
    Q = xy

    and the integral becomes

    ∫[0,9]∫[0,√x] (∂Q/∂x - ∂P/∂y) dy dx
    = ∫[0,9]∫[0,√x] (y - 2y) dy dx
    = ∫[0,9]∫[0,√x] -y dy dx
    = ∫[0,9] -x/2 dx
    = -x^2/4 [0,9]
    = -81/4

Answer This Question

First Name:
School Subject:

Related Questions

More Related Questions

Post a New Question