Posted by **mary** on Thursday, June 6, 2013 at 2:21pm.

(3b+1)^2=16

- elementary algebra -
**Kuai**, Thursday, June 6, 2013 at 2:38pm
(3b+1) (3b +1) = 16

9b^2 + 3b +3b + 1 = 16

9b^2 + 6b + 1 = 16

9b^2 + 6b + 1 -16 = 16-16

9b^2 + 6b -15 = 0

3(3b^2 + 2b -5) = 0

3(b-1)(3b+5) = 0

b - 1 = 0 3b + 5 = 0

b -1+1 = 0 + 1 3b + 5 - 5 = 0-5

b = 1 3b = -5

3b/3 = -5/3

b = -5/3

b = 1, -5/3

- elementary algebra -
**Steve**, Thursday, June 6, 2013 at 3:15pm
(3b+1)^2=16

3b+1 = ±4

3b+1 = 4

b = 1

or

3b+1 = -4

b = 5/3

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