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Chemistry
If 37.0 mL of HCl is used to neutralize 25.0 mL of 0.09345M LiOH. What is the concentration of the acid
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mL acid x M acid = mL base x M base.
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If 37.0 mL of HCl is used to neutralize 25.0 mL of 0.09345M LiOH. What is the concentration of the acid
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25 ml HCl x 1L/1000mL x .200HCl/1L = .005 mol HCl.
Using the balanced equation from this, how many moles of NaOh will you need to
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