Posted by **David** on Wednesday, June 5, 2013 at 10:24pm.

Calculate the total constant force needed to accelerate a vehicle with mass 1400kg and tractive resistance of 320N from 19km/h to 95km/h over a distance of 0.8km on a horizontal plane.show working?

- fundamentals -
**herp_derp**, Thursday, June 6, 2013 at 12:21am
ah...DANNY..we meet again...

not sure if this is right but i'll take a shot at it...

1. convert all the info into MKS units (MKS = meters, kilograms, seconds)

19 km/hr = 5.277 m/s

95 km/hr = 26.388 m/s

0.8 km = 800 m

2. start with this equation:

vf^2 = vi^2 + 2ad

then, solve for "a"

a = (vf^2 - vi^2)/(2d)

plug in the numbers...

((26.388 m/s)^2 - (5.277 m/s)^2)/(2 x 800 m) = 0.4178 m/s^2

3. then we take care of those vectors...

Fo - Fe = Fc

ma - Fe = Fc

(1400 kg)(0.4178 m/s^2) - (320 N) = 264.92 N

-----

remember DANNY.....HERP THE DERP!!!

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