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March 29, 2015

March 29, 2015

Posted by **DANNY** on Wednesday, June 5, 2013 at 9:20pm.

A) Its speed in m/s

u = 85km/h

= 85km/h * 1000m/km/ 60s/min * 60min/m/h

= 85000/ 3600

= 23.61

ANS = 23.61m/s

B) How many meters will it travel in 8 seconds

= 23.61m/s * 8s

ANS = 188.88m

C) How long (in seconds) will it take to cover 2km

2km = 2000m

= 2000m/ 23.61s

= 84.70s

ANS = 84.70s

D) The average speed in km/h, if the time to travel 140km is 1 hour and 50 minutes.

average speed = Distance/ Time

= 140km/ 1.5hours

= 93.333km/h

ANS = 93.333km/h

Please let me know if I used the correct formula and have the right answer. Thanks.

2. A car is traveling at 95km/h. Find the following:

A) its speed in m/s

u = 95km/h

= 95km/h * 1000m/km/ 60s/min * 60min/m/h

= 95000/ 3600

= 26.38

ANS = 26.38m/s

B) How many meters will it travel in 6 seconds

= 26.38m/s * 6 s

= 158.28m

ANS = 158. 28m

C) How long it takes to cover 5km

5km = 5000m

= 5000m/ 26.38m/s

= 189.537s

= 3min 9.54s

ANS = 3minutes 9.54 seconds

D) The average speed in km/h, if the time to travel 250km is 2 hours and 40 minutes

average speed = distance/ time

= 250km/ 2hr 40min

= 250km/2.40

= 104.166km/h

ANS = 104.17km/h

Please let me know if I have used the correct formula and have the right answer. Thanks.

- Physics -
**herp_derp**, Wednesday, June 5, 2013 at 9:45pmok,ok,ok....lad listen up

lets see how ya did here...

THESE ARE THE CORRECT ANSWERS...

1a) 85 km/hr = 23.61 m/s (HINT: from km/hr to m/s just divide by 3.6)

1b) d = vt = (23.61)(8) = 188.88 m

1c) t = d/v = (2000)/(23.61) = 84.7 s

1d) v = d/t = (140)/(1.83) = 76.5 km/hr (HINT: 1 hr 50 min IS NOT 1.5 hr, rather its 1.83 hr)

2a) 95 km/hr = 26.38 m/s

2b) d = vt = (26.38)(6) = 158.28 m

2c) t = d/v = (5000)/(26.38) = 189.537 s = 3 min 9.537 s

2d) v = d/t = (250)/(2.667) = 93.73 km/hr (HINT: AGAIN, 2 hr 40 min IS NOT 2.4 hr, rather 2.667 hr)

-------

Overall, you did well (6/8). You just need to watch out with your conversions.

And always remember...HERP THE DERP!! (k..im done....but good luck in physics!)

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