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September 14, 2014

September 14, 2014

Posted by **Ashley** on Wednesday, June 5, 2013 at 4:02pm.

- Physics -
**herp_derp**, Wednesday, June 5, 2013 at 10:09pmah...i remember these days of vectors...

anyway, i THINK (not so sure thou) that this is the answer...

well, if 30 N is pointed downward and 40 N is pointed sideways, i think you would need to use the Pythagorean theorem.

so...

Let Vr = (Resultant vector)

Let Vy = the the block's weight

Let Vx = the parallel force

(Vr)^2 = (Vy)^2 + (Vx)^2

Vr = squ-root( Vy^2 + Vx^2)

squ-root( 30^2 + 40^2 ) = 50 N

THEREFORE....

the magnitude of the force is 50 N

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and always remember...HERP THE DERP!!!

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